Cylindrical coordinates of line through a point?

Click For Summary
SUMMARY

The discussion focuses on deriving the cylindrical coordinates of a line through the point (1,1,0) that is parallel to the z-axis. The cylindrical coordinates are established as (√2, ∏/4, z), with the ordinary equation represented as r = √2 and θ = ∏/4. The participants clarify that the parametric equation should be expressed in the form r = (√2, ∏/4, z) where z varies, rather than attempting to add non-Cartesian coordinates. The conversation emphasizes the importance of distinguishing between ordinary and parametric forms in cylindrical coordinates.

PREREQUISITES
  • Understanding of cylindrical coordinates
  • Familiarity with parametric equations
  • Basic knowledge of vector representation in three dimensions
  • Ability to convert between Cartesian and cylindrical coordinates
NEXT STEPS
  • Study the derivation of cylindrical coordinates from Cartesian coordinates
  • Learn how to express lines in parametric form in cylindrical coordinates
  • Explore the differences between ordinary and parametric equations
  • Practice problems involving lines parallel to axes in cylindrical coordinates
USEFUL FOR

Students studying multivariable calculus, educators teaching coordinate systems, and anyone seeking to understand the application of cylindrical coordinates in three-dimensional geometry.

whig4life
Messages
14
Reaction score
0

Homework Statement



Use cylindrical coordinates to describe the line through the point (1,1,0) and parallel to the z-axis.

Homework Equations



How does one go about this? Even my course book was unclear about this. Any general overview about how to do such a question will be helpful.

The Attempt at a Solution



The z-axis is (0,0,1) while the cylindrical coordinates are (√2, ∏/4, z)

Now, is the solution in the form of and r = (√2, ∏/4, 0) + (0,0,1)t? Or am I completely lost? (haha)
 
Last edited:
Physics news on Phys.org
Draw a line r from the origin to the line x = 1 at some point y. Connect that point with a line r going to the origin.
What is r(y)? Or - hint - r2(y)?
Then, can you express θ in terms of y?
Finally you wind up with f(r) = (const.) + g(θ).

EDIT: oh dear, I assumed the line parallel to the y axis. Never mind ...
 
Last edited:
hi whig4life! :smile:
whig4life said:
The z-axis is (0,0,1)

sorry to be pernickety, but no, (0,0,1) is a point, isn't it? :wink:

while the cylindrical coordinates are (√2, ∏/4, z)

correct :smile:
Now, is the solution in the form of and r = (√2, ∏/4, 0) + (0,0,1)t? Or am I completely lost? (haha)

it depends whether you want a parametric equation or an ordinary one

the ordinary equation is r = √2, θ = ∏/4

(just as in cartesian coordinates it would be x = y = 1)

the parametric equation is not (r,θ,z) = (√2, ∏/4, 0) + (0,0,1)t

you can't add non-cartesian coordinates (try adding (1,0,0) to (1,∏,0) … do you get (2,∏,0) ?)

it's (r,θ,z) = (√2, ∏/4, …?… ) ?
 
I was told: The answer should probably be given in parametric form

r = something, theta = something, z = something

So, any ideas? I've exhausted all my resources trying to look for this maybe a better mind can see it more clearly.
 
Last edited:
hi whig4life! :smile:

(just got up :zzz:)

the parametric equation would be r = √2, θ = ∏/4, z = … ?
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K