D/dx of the integral from 0 to x^3 of ln(t^2 + 1)

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The discussion focuses on finding the derivative of the integral from 0 to x³ of ln(t² + 1) dt. The correct application of the Fundamental Theorem of Calculus and the chain rule leads to the result of 3x² ln(x⁶ + 1). Participants emphasize the importance of correctly identifying the upper limit as x³, which is crucial for accurate differentiation.

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\int_{0}^{x3} ln(t^2 + 1) dt

^take the derivative of that...sorry the upper-limit is x3 NOT 2x.

how is the answer 3x2 ln (x6 + 1) ?
 
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Use the chain rule and the fundamental theorem of calculus. And show us your attempt.
 

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