D'Alembert's solution of the wave equation

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Discussion Overview

The discussion centers on D'Alembert's solution of the wave equation, specifically addressing the initial conditions for displacement and velocity. Participants explore the implications of these conditions on the uniqueness of the solution.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions whether the initial velocity condition should imply that the time derivative of the initial displacement function η0(x) is zero.
  • Another participant clarifies that the time derivative is applied to the full function η(x,t) at t=0, not directly to η0(x), and emphasizes that both initial conditions are independent constraints necessary for a unique solution.
  • A later reply acknowledges the clarification regarding the independent nature of the constraints.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between the initial displacement and velocity conditions, indicating that the discussion remains unresolved regarding their connection.

Contextual Notes

Participants highlight the need for both initial conditions to ensure a unique solution, but the exact nature of their independence and implications is not fully agreed upon.

Gear300
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For a wave equation η(u,v) = f1(u) + f2(v) where u = x - ct and v = x + ct, consider an initial displacement η = η0(x) and an initial velocity ∂tη = [itex]\dot{η_{0}}(x)[/itex].

I'm a little confused with the velocity initial condition; shouldn't the time derivative of η0(x) be 0?
 
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Gear300 said:
For a wave equation η(u,v) = f1(u) + f2(v) where u = x - ct and v = x + ct, consider an initial displacement η = η0(x) and an initial velocity ∂tη = [itex]\dot{η_{0}}(x)[/itex].

I'm a little confused with the velocity initial condition; shouldn't the time derivative of η0(x) be 0?
I think the problem you are having is that the explicit time derivative of a function of only x is zero. But note the explicit time derivative is not applied to the [itex]η_{0}(x)[/itex] function, it is applied to the [itex]η(x,t)[/itex] function at t=0, and that is just given the name [itex]\dot{η_{0}}(x)[/itex]. You could call it anything-- call it h(x) if you like. The key point is, it is a constraint on the [itex]η(x,t)[/itex] function, without which you cannot get a unique solution. Think of the two constraints as being on η(x,t) at t=0 and on ∂tη(x,t) at t=0.
 
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Thanks for the reply. I figured the dot was implying the time derivation of the first constraint.
 
So do you see now that this is not the case? There are two independent constraints there, they have no connection to each other other than that they are both taken as constraints on the full solution.
 
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