Damped Oscillator: Var of Area in Phase Space Over Time

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SUMMARY

The discussion centers on the mathematical derivation of the area in phase space for a damped simple harmonic oscillator, represented by the equation A(t) = A(0) e^{(-r/m)t}. The relevant equations of motion are given as \dot{x} = (1/m) y and \dot{y} = -kx - (r/m) y. Participants express confusion regarding the concept of an orbit having an area and the integration process required to derive the area over time. The initial misunderstanding stems from a misquoted equation, which was later corrected but did not clarify the participant's confusion.

PREREQUISITES
  • Understanding of damped harmonic motion
  • Familiarity with phase space concepts
  • Knowledge of differential equations
  • Basic integration techniques
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  • Study the derivation of phase space areas in damped oscillators
  • Learn about the mathematical properties of orbits in phase space
  • Explore the integration of differential equations related to oscillatory motion
  • Investigate the implications of damping on energy loss in oscillators
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Students of physics, particularly those studying classical mechanics and oscillatory systems, as well as educators looking to clarify concepts related to phase space and damped motion.

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Homework Statement


Show that the area in phase space of a cluster of orbits for the damped simple harmonic oscillator given in the lecture varies in time as:
A(t) = A(0) e^{(-r/m)t}

Homework Equations


\dot{x} = (1/m) y
\dot{y} = -kx - (r/m) y

The Attempt at a Solution


I don't understand the question. I don't see how an orbit - which is a line - can have an area. I'm guessing that the result is found by some integration of the given equations, but since I don't see how the statement of the question makes any sense, I can't follow the logic.

Edit: bah. Copied down the wrong equation. The correct one is now quoted. Still, knowing the right one isn't enlightening me on what to do.
 
Last edited:
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Nobody?

Is the question nonsense, or have I not explained properly?
 

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