Damping Constant: Solving for b Homework

Click For Summary
To solve for the damping constant (b), the relevant equations must account for the decrease in amplitude due to damping. The amplitude has decreased to 80% of its original height (0.1m) after 10 oscillations, indicating that the system is experiencing damping. The initial equations provided do not incorporate damping effects, which is why they cannot be used to find b. A different approach or formula that includes damping must be utilized to arrive at the correct value, which is indicated to be 0.71 kg/s in the textbook. Understanding the relationship between amplitude reduction and damping is crucial for solving this problem effectively.
Tylerladiesman217
Messages
3
Reaction score
0

Homework Statement


I am solving for the damping constant (b). The amplitude has decreased to 80% of its original height (0.1m) after 10 oscillations. The mass is 2 kg, k is 5000 N/m, w is 50 rads/s, T = pi/25 s.

Homework Equations


x = 0.1cos(50t)
v = -5sin(50t)
a = -250cos(50t)

The Attempt at a Solution


I am not sure what equation to use, I tried
w = ((k/m)-(b^2/4(m)^2))^1/2
 
Physics news on Phys.org
Helo Tyler, :welcome:

With those equations you'll never be able to solve for the damping constant -- it doesn't appear !
Where do you think it should be sitting ?
 
BvU said:
Helo Tyler, :welcome:

With those equations you'll never be able to solve for the damping constant -- it doesn't appear !
Where do you think it should be sitting ?
I'm not sure, the answer in the back of the book is 0.71 kg/s. I think that I might need to use a different formula, but I'm not sure.
 
What I meant is that your relevant equations feature a constant amplitude: no damping.
 
BvU said:
What I meant is that your relevant equations feature a constant amplitude: no damping.
Those are the equations assuming no damping. Maybe they aren't relative...
 
Tylerladiesman217 said:
I am solving for the damping constant (b). The amplitude has decreased to 80% of its original height (0.1m) after 10 oscillations
So you can not use ##x = 0.1\cos(50t)## . The link I gave you should help you further...
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
Replies
3
Views
801
  • · Replies 2 ·
Replies
2
Views
3K
Replies
17
Views
2K
Replies
9
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
9
Views
2K
Replies
7
Views
1K
Replies
3
Views
961
  • · Replies 14 ·
Replies
14
Views
2K