Damping Constant: Solving for b Homework

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To solve for the damping constant (b), the relevant equations must account for the decrease in amplitude due to damping. The amplitude has decreased to 80% of its original height (0.1m) after 10 oscillations, indicating that the system is experiencing damping. The initial equations provided do not incorporate damping effects, which is why they cannot be used to find b. A different approach or formula that includes damping must be utilized to arrive at the correct value, which is indicated to be 0.71 kg/s in the textbook. Understanding the relationship between amplitude reduction and damping is crucial for solving this problem effectively.
Tylerladiesman217
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Homework Statement


I am solving for the damping constant (b). The amplitude has decreased to 80% of its original height (0.1m) after 10 oscillations. The mass is 2 kg, k is 5000 N/m, w is 50 rads/s, T = pi/25 s.

Homework Equations


x = 0.1cos(50t)
v = -5sin(50t)
a = -250cos(50t)

The Attempt at a Solution


I am not sure what equation to use, I tried
w = ((k/m)-(b^2/4(m)^2))^1/2
 
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Helo Tyler, :welcome:

With those equations you'll never be able to solve for the damping constant -- it doesn't appear !
Where do you think it should be sitting ?
 
BvU said:
Helo Tyler, :welcome:

With those equations you'll never be able to solve for the damping constant -- it doesn't appear !
Where do you think it should be sitting ?
I'm not sure, the answer in the back of the book is 0.71 kg/s. I think that I might need to use a different formula, but I'm not sure.
 
What I meant is that your relevant equations feature a constant amplitude: no damping.
 
BvU said:
What I meant is that your relevant equations feature a constant amplitude: no damping.
Those are the equations assuming no damping. Maybe they aren't relative...
 
Tylerladiesman217 said:
I am solving for the damping constant (b). The amplitude has decreased to 80% of its original height (0.1m) after 10 oscillations
So you can not use ##x = 0.1\cos(50t)## . The link I gave you should help you further...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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