DC circuit steady state (resistors and capacitors)

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SUMMARY

The discussion focuses on analyzing a DC circuit with a voltage source (V_s) of 10V, two resistors (R_1 and R_2), and a capacitor (C). At steady state, the capacitor behaves as an open circuit, resulting in no current flow through the middle branch. Consequently, the voltage across the capacitor is 10V, while the voltage drop across R_1 is 0V, and R_2 experiences a full 10V drop.

PREREQUISITES
  • Understanding of DC circuit analysis
  • Knowledge of capacitor behavior in steady state
  • Familiarity with Ohm's Law
  • Basic circuit diagram interpretation skills
NEXT STEPS
  • Study the behavior of capacitors in AC circuits
  • Learn about voltage dividers in resistor networks
  • Explore transient analysis of RC circuits
  • Investigate the effects of varying resistor values on voltage drops
USEFUL FOR

Electrical engineering students, circuit designers, and hobbyists interested in understanding DC circuit behavior, particularly in relation to capacitors and resistors.

pyroknife
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I have attached the picture of the circuit.
I'm trying to figure out the steady state voltages across the 2 resistors and the capacitor.

V_s is given to be 10V DC.

At steady state in a DC circuit, a capacitor acts as an open. When that happens, we shouldn't expect any current to flow through the middle branch right?
If so, then that means there would be a 10V drop across 'C' and 0V drop across R_1. R_2 would also experience a 10V drop.
 

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Very good.
 

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