DC Circuits Question (internal resistance)

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SUMMARY

The discussion focuses on calculating the currents through resistors R1 and R2 in a DC circuit with given values of R1 = 37Ω, R2 = 16Ω, V1 = 9.0V, and V3 = 6.0V. The correct current through R1 is determined to be 0.16216 A, while the calculation for R2 yields an incorrect current of 0.375 A. The participants suggest that there may have been a mix-up in the resistor values, and they recommend applying Kirchhoff's Voltage Law (KVL) for accurate analysis.

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KierstenKudos
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Homework Statement



Determine the magnitudes and directions of the currents through R1 and R2 in Fig. 19-47, where R1 = 37 and R2 = 16 .

Figure 19-47
(image attached)

V1 = 9.0 V
V3 = 6.0 V
R1 = 37 [tex]\Omega[/tex]
R2 = 16 [tex]\Omega[/tex]

Homework Equations



V = IR

The Attempt at a Solution



V = IR
6.0 V = (37[tex]\Omega[/tex]) I
.16216 A = I [tex]_{}1[/tex](correct)

V = IR
6.0 = (16[tex]\Omega[/tex]) I
.375 A = I[tex]_{}2[/tex] (incorrect)
 

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KierstenKudos said:

The Attempt at a Solution



V = IR
6.0 V = (37[tex]\Omega[/tex]) I
.16216 A = I [tex]_{}1[/tex](correct)

V = IR
6.0 = (16[tex]\Omega[/tex]) I
.375 A = I[tex]_{}2[/tex] (incorrect)
That's weird, I would say I1 is incorrect and I2 is correct. Did you get the 16Ω and 37Ω values reversed perhaps?

Kirchof's Voltage Law (KVL) would be useful here.
 

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