De broglie and electron transitions

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    De broglie Electron
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SUMMARY

The discussion centers on the hypothesis that electron transitions from high to low energy states in hydrogen atoms may be influenced by interactions with dark energy particles. Key equations from Niels Bohr's model are referenced, including the orbital radius formula (r = n^2 h^2 / (8 pi x epsilon x me^2)) and energy levels (Energy = -E/n^2). The de Broglie wavelength of the electron is calculated as approximately 10^-11 meters, leading to a derived area of 10^-22 square meters. The participants debate the plausibility of dark energy's role in these transitions, with Marlon emphasizing the high probability of spontaneous transitions and Kurious proposing a mechanism for the timing of these events.

PREREQUISITES
  • Niels Bohr's model of the hydrogen atom
  • De Broglie wavelength concept
  • Understanding of dark energy and its properties
  • Basic principles of quantum mechanics
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  • Explore quantum mechanical calculations related to electron transitions
  • Study the implications of dark energy in quantum physics
  • Research the de Broglie wavelength and its applications in particle physics
  • Investigate X-ray photo-ionization cross-sections for various atoms
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Physicists, quantum mechanics researchers, and students interested in the interactions between particles and energy states in atomic structures.

kurious
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Is it possible that electron transitions from a high energy state to a low energy state are caused by the electrons interacting with some other partilces in the space around atoms.Let's look at the case of a hydrogen atom:
According to Niels Bohr, for an electron, r = n^2 h^2 / (8 pi x epsilonx me^2)
and Energy = - E / n^2

So in Bohr's model an electron with a greater energy (an electron that has undergone a transition) has a greater value of orbital radius.

The de broglie wavelength of the electron is given by lambda = h/mv
and is about 10^-11 metres.This a length we can associate with the electron.
So if we square the de Broglie wavelength we get an area we can associate with the electron and this is 10^-22 square metres.

Now, space is filled with dark energy, at a density of 10^-27 kg per cubic metre.If the area of our electron was facing 1m^2 of dark energy this would
be 10^-22 x 10^-27 = 10^-49 kg of the mass of the total mass of dark energy in a cubic metre.Nobody knows what dark energy really is but let's suppose
that like anything else in the universe that has energy it consists of particles of some sort.These particles must move close to the speed of light because dark energy is considered by experts to be more energy-like than mass-like.
At the speed of light,10^8 m/s, 10^49 kg of dark energy particles could strike
an area equal to the de Broglie wavelength squared in 10^-8 seconds.
Thus is the maximum force the dark energy particles can exert on the
area (assuming the dark energy particles are all repelled by the coulomb charge) is F = m x change of velocity/ time = 10^-49 x 10^8/10^-8
= 10^-33 Newtons.The acceleration this would produce on an electron of mass 10^-31 kg is acceleration = Force/mass = 10^-2 m/s^2.
A transition from n = 2 to n= 1 in the Bohr model of hydrogen amounts to a distance of about 10^-10 m.An acceleration of 10^-2 m/s^2 acting on an electron would thus move it back to the ground state in a minimum time of
10^-8 seconds.This is what is observed.Can anyone come up with a quantum mechanical calculation that could give some more convincing evidence for dark energy causing an electronic transition from an excited to a ground state.
 
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kurious said:
Is it possible that electron transitions from a high energy state to a low energy state are caused by the electrons interacting with some other partilces in the space around atoms.Let's look at the case of a hydrogen atom:
According to Niels Bohr, for an electron, r = n^2 h^2 / (8 pi x epsilonx me^2)
and Energy = - E / n^2

So in Bohr's model an electron with a greater energy (an electron that has undergone a transition) has a greater value of orbital radius.

The de broglie wavelength of the electron is given by lambda = h/mv
and is about 10^-11 metres.This a length we can associate with the electron.
So if we square the de Broglie wavelength we get an area we can associate with the electron and this is 10^-22 square metres.

Now, space is filled with dark energy, at a density of 10^-27 kg per cubic metre.If the area of our electron was facing 1m^2 of dark energy this would
be 10^-22 x 10^-27 = 10^-49 kg of the mass of the total mass of dark energy in a cubic metre.Nobody knows what dark energy really is but let's suppose
that like anything else in the universe that has energy it consists of particles of some sort.These particles must move close to the speed of light because dark energy is considered by experts to be more energy-like than mass-like.
At the speed of light,10^8 m/s, 10^49 kg of dark energy particles could strike
an area equal to the de Broglie wavelength squared in 10^-8 seconds.
Thus is the maximum force the dark energy particles can exert on the
area (assuming the dark energy particles are all repelled by the coulomb charge) is F = m x change of velocity/ time = 10^-49 x 10^8/10^-8
= 10^-33 Newtons.The acceleration this would produce on an electron of mass 10^-31 kg is acceleration = Force/mass = 10^-2 m/s^2.
A transition from n = 2 to n= 1 in the Bohr model of hydrogen amounts to a distance of about 10^-10 m.An acceleration of 10^-2 m/s^2 acting on an electron would thus move it back to the ground state in a minimum time of
10^-8 seconds.This is what is observed.Can anyone come up with a quantum mechanical calculation that could give some more convincing evidence for dark energy causing an electronic transition from an excited to a ground state.

This area you are talking about is another speculation. What is your proof for making such a statement.

But let's suppose you are "right". I don't see how this area can be coupled to an interaction of certain particles with this electron?

Besides a transition from excited to groundstate has very high probability so that it occurs automatically. Why trigger these events ?


regards
marlon
 
Marlon:
This area you are talking about is another speculation. What is your proof for making such a statement.

Kurious:
The de Broglie wavelength itself was speculation when it first came out.

Marlon:
Besides a transition from excited to groundstate has very high probability so that it occurs automatically. Why trigger these events ?

kURIOUS:
I am talking about a mechanism that can account for the time taken for the transition.

Marlon:
I don't see how this area can be coupled to an interaction of certain particles with this electron?


Kurious:
In an EM wave the electric field is spread out over the length of the wave.
I am asking by analogy if the de Broglie wavelength says that the electric field of
an electron can be spread out over that wavelength so that interactions with other electrically charged particles can occur in a small area given by the square of the de Broglie wavelength.
 
kurious said:
Marlon:
This area you are talking about is another speculation. What is your proof for making such a statement.

Kurious:
The de Broglie wavelength itself was speculation when it first came out.

Marlon:
Besides a transition from excited to groundstate has very high probability so that it occurs automatically. Why trigger these events ?

kURIOUS:
I am talking about a mechanism that can account for the time taken for the transition.

Marlon:
I don't see how this area can be coupled to an interaction of certain particles with this electron?


Kurious:
In an EM wave the electric field is spread out over the length of the wave.
I am asking by analogy if the de Broglie wavelength says that the electric field of
an electron can be spread out over that wavelength so that interactions with other electrically charged particles can occur in a small area given by the square of the de Broglie wavelength.


Your last statement is untrue. The EM-interactions are GLOBAL. Besides the de Broglie-wavelength describes the particle in itself (not the way it can interact), not the electric field. You got to think of these two things as some kind of dual aspects. The are different , yet they are used to describe the same thing (electron)

regards
marlon
 
kurious said:
So if we square the de Broglie wavelength we get an area we can associate with the electron and this is 10^-22 square metres.

Not sure if this helps much, but X-ray photo-ionization cross-sections for most atoms is between 1 and 50 x 10e-28 sq-cm. Hydrogen and helium are not observed by conventional, fixed-wavelength XPS which suggests their cross-section are smaller still. The X-rays for XPS are most often Aluminum K-alpha with 8.3 ang wavelength and 1486 eV of energy.
 
This is quite clearly too speculative.

- Warren
 

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