What is the Wavelength of a 30 keV Electron?

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SUMMARY

The wavelength of a 30 keV electron can be estimated using the de Broglie wavelength formula, where the momentum p is related to wavelength λ by p = h/λ. The energy E of the electron is given by E = hf, leading to a frequency f of approximately 7.619 x 1018 Hz. To find the wavelength, one must first convert the energy from keV to joules and calculate the speed of the electron using its mass-energy relationship, rather than assuming it travels at the speed of light.

PREREQUISITES
  • Understanding of de Broglie wavelength and its formula
  • Knowledge of energy conversion from keV to joules
  • Familiarity with the relationship between energy, frequency, and momentum
  • Basic concepts of particle-wave duality in quantum mechanics
NEXT STEPS
  • Learn how to convert electron volts (eV) to joules (J)
  • Study the de Broglie wavelength calculation in detail
  • Explore the mass-energy equivalence principle (E=mc2)
  • Investigate the behavior of electrons in quantum mechanics and their speed calculations
USEFUL FOR

Students and educators in physics, particularly those focusing on quantum mechanics, as well as anyone interested in understanding the wave-particle duality of electrons.

Pyroadept
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Homework Statement


Estimate the wavelength of a 30 keV electron.


Homework Equations


p = h/λ
E = hf

The Attempt at a Solution


The electron has 30 keV of mass-energy.
As it is acting as a particle-wave, E = hf, so f = E/h = 30,000x1.6x10^-19/6.3X10^-34 = 7.619x10^18 Hz

Now, v = fλ, so λ = v/f, but this is where I run into a problem, as I'm not told what speed the electron is traveling at - do I assume speed of light, or is there some other way?
 
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Pyroadept said:
Estimate the wavelength of a 30 keV electron.

Now, v = fλ, so λ = v/f, but this is where I run into a problem, as I'm not told what speed the electron is traveling at - do I assume speed of light, or is there some other way?

Hi Pyroadept! :smile:

If you can convert the eV into J, and if you know the mass of an electron, then you can calculate the speed from the energy. :wink:
 

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