De Broglie wave length, average electron energy and momentum calculation

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SUMMARY

The discussion focuses on calculating the average energy, momentum, and de Broglie wavelength of an electron in an electron gas at thermal equilibrium at a temperature of 315K. The average electron energy is calculated using the formula 3*kT/2, resulting in 0.0402 eV. The average momentum calculation requires the mass of the electron, emphasizing that momentum is a vector quantity. The de Broglie wavelength calculation is implied but not explicitly detailed in the discussion.

PREREQUISITES
  • Understanding of thermal equilibrium in electron gases
  • Familiarity with the Boltzmann constant (k)
  • Knowledge of the de Broglie wavelength formula
  • Basic principles of momentum as a vector quantity
NEXT STEPS
  • Learn how to calculate the de Broglie wavelength using the formula λ = h/p
  • Study the relationship between temperature and electron energy in statistical mechanics
  • Explore the concept of momentum in quantum mechanics
  • Investigate the implications of electron gas behavior in solid-state physics
USEFUL FOR

Students in physics, particularly those studying quantum mechanics and statistical mechanics, as well as educators looking to enhance their understanding of electron behavior in thermal systems.

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Homework Statement


Calculate the average electron energy of an electron in an electron gas at thermal equilibrium. Temperature is 315K. Calculate the average electron momentum. Calculate the de Broglie wave length of the electron

Homework Equations


3*kT/2

The Attempt at a Solution


[/B]
Part 1) 3*(8.62*10^-5)*315K/2 = .0402 eV

Part 2) I'm unsure of how to calculate average momentum. Should I use the mass of the electron?
 
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Hint: Momentum is a vector quantity.
 

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