De Broglie Wavelenght of a 5.5Mev

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Homework Help Overview

The discussion revolves around calculating the de Broglie wavelength of a 5.5 MeV alpha particle emitted from an Am-241 nucleus, and whether this particle could exist within the nucleus, which has a specified diameter of 1.6 x 10-14 m.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the de Broglie wavelength using a formula involving Planck's constant and momentum. Some participants suggest using classical momentum formulas for nonrelativistic particles, while others introduce the uncertainty principle to question the spatial resolution of the particle.

Discussion Status

Participants are exploring different approaches to the problem, including classical mechanics and quantum principles. There is a calculation presented for the wavelength, and a comparison is made with the nucleus diameter, but no consensus has been reached regarding the implications of these findings.

Contextual Notes

There is a discussion about the nonrelativistic nature of the alpha particle and the implications of the calculated wavelength in relation to the size of the nucleus.

diegoarmando
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Calculate the de Broglie wavelength of a 5.5 Mev alpha particle emitted from Am (241) nucleus, could this particle exist with inside the Am (241) nucleus (diameter = 1.6x10^-14m)?


the wavelength:
Lambda=h/p = (hc) / (sqrt[2mc^2)xeV)
= 1240 / sqrt(2x3727.38x10^6x5.5x20^6)

?
 
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Well...

The alpha particle is nonrelativistic since KE/mc^2 = 10^-3, so you can use the classical formula for momentum p = sqrt(2mKE).

Use this momentum to find the deBroglie wavelength.
 
Use the uncertainty principle to find out the spatial resolution of a particle with this momentum.

(hands wave around)

x ~= h/(4*pi*p)

Is this x larger than the diameter of the nucleus?
 
Last edited:
I find 6x10^-15 m for lambda, so the diameter of Am is 1.6x10^-14, so the wave length is less than the diameter, is that mean the wavelength can be exist inside the Am nucleus?
 

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