De Broglie wavelength, velocity of electron

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SUMMARY

The discussion focuses on calculating the de Broglie wavelength of a neutron and the velocity of an electron. The de Broglie wavelength formula, λ = h/(mv), where h is Planck's constant (6.626068 x 10^-34 J·s), is applied to both particles. The neutron's wavelength was calculated at 2.64 x 10^-15 meters, while the electron's velocity was determined to be 3.22 x 10^6 m/s for a de Broglie wavelength of 225.7 pm. Participants shared their calculations and sought confirmation of their results.

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  • Understanding of de Broglie wavelength and its significance in quantum mechanics
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  • Basic knowledge of particle physics, specifically regarding neutrons and electrons
  • Ability to perform unit conversions, particularly between picometers and meters
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  • Study the implications of de Broglie wavelength in quantum mechanics
  • Learn about the relationship between wavelength and momentum in quantum particles
  • Explore the concept of wave-particle duality and its historical context
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Students and educators in physics, particularly those focusing on quantum mechanics, as well as researchers exploring wave-particle duality and its applications in modern physics.

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Homework Statement



Question 1) Calculate the de Broglie wavelength of a neutron (mn = 1.67493×10-27 kg) moving at one fiftieth of the speed of light (c/50).


Question 2) Calculate the velocity of an electron (me = 9.10939×10-31 kg) having a de Broglie wavelength of 225.7 pm.


Homework Equations



Wavelength of a particle = Plancks constant/(mass)(velocity)
Plancks constant= 6.626068 x 10^-34
I know this, and it should be plug and chug but my answer is always wrong...any help would be greatly appreciated!

The Attempt at a Solution

 
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I got..

1) 2.64*10^-15
2) 3.22*10^6 m/s

what did you get?
 
Plug it into

nh/2(pi)m(e-)r(e-)

n= proton number
h= 6.62 x 10^-34
m= e- mass 9.11 x 10^-31 m
r= Bohr radius 5.2 x 10^-11 m
 

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