Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: DE with an initial condition

  1. Dec 11, 2006 #1
    I am asked to solve this DE with the initial condition of y(1) = 1.

    [tex](x+y)^2dx + (2xy + x^2-1)dy = 0[/tex]

    So, after working the problem out, I came to this as an answer:
    [tex]F(x,y)=\frac{1}{3}x^3 + x^2y + xy^2-y[/tex]

    My question is what do I do with the initial condition. I assume that I am just suppossed to plug 1 in somewhere, but the syntax of the initial condition does not seem very intuitive to me. What does y(1) = 1 mean?

    Thank you
     
  2. jcsd
  3. Dec 11, 2006 #2

    dextercioby

    User Avatar
    Science Advisor
    Homework Helper

    They hint towards a x=x(y) solution.

    Daniel.
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook