[tex](x+y)^2dx + (2xy + x^2-1)dy = 0[/tex]

So, after working the problem out, I came to this as an answer:

[tex]F(x,y)=\frac{1}{3}x^3 + x^2y + xy^2-y[/tex]

My question is what do I do with the initial condition. I assume that I am just suppossed to plug 1 in somewhere, but the syntax of the initial condition does not seem very intuitive to me. What does y(1) = 1 mean?

Thank you