Decomposing a Series Using Riemann's Rearrangement Theorem

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Homework Help Overview

The discussion revolves around computing the sum of a specific series involving alternating signs and the application of Riemann's Rearrangement Theorem, which is relevant due to the series being absolutely convergent.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants express uncertainty about how to begin the problem and question the correctness of the series' sign pattern. There is an attempt to decompose the series into two separate sums based on odd and even indexed terms.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the series and suggesting a breakdown into two sums. Some guidance has been offered regarding the structure of the sums, but no consensus has been reached.

Contextual Notes

There is a note of confusion regarding the series' sign pattern, which may affect the approach to finding the sum. Participants are also considering the implications of absolute convergence in relation to Riemann's Rearrangement Theorem.

the_kid
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Homework Statement


I'm trying to compute the sum of the following series:

S=1+[itex]\frac{1}{4}[/itex]-[itex]\frac{1}{16}[/itex]-[itex]\frac{1}{64}[/itex]+[itex]\frac{1}{256}[/itex]


Homework Equations





The Attempt at a Solution


I'm not really sure how to begin this one. I know it probably involves Riemann's Rearrangement Theorem since this series is absolutely convergent.
 
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the_kid said:

Homework Statement


I'm trying to compute the sum of the following series:

S=1+[itex]\frac{1}{4}[/itex]-[itex]\frac{1}{16}[/itex]-[itex]\frac{1}{64}[/itex]+[itex]\frac{1}{256}[/itex]


Homework Equations





The Attempt at a Solution


I'm not really sure how to begin this one. I know it probably involves Riemann's Rearrangement Theorem since this series is absolutely convergent.

Are the successive signs really ++--+? What happens after that? Are you sure you copied the question correctly?

RGV
 
My apologies; I should have been clearer in my original post.

The signs are ++-- ++-- ...
 
Any help?
 
Okay, so I think that if you think about it as the sum of two sums, that will help...

think of the first sum as the sum of every odd indexed term, and the second sum as the sum of every even indexed term.

S1 = 1-1/16+1/256...
S2 = 1/4-1/64+1/(16*64)...

thus, the first sum will be

S1 = [itex]\sum[/itex][itex](-1/16)[/itex]n from n = 0 to ∞.

and the second, I'll let you figure out. but I think that this should help. (note, the second one needs a constant out front.

hope this helps!
 

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