Defibrillator: charge, capacitance, power and current problem

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Ventricular fibrillation is a life-threatening heart condition that can be treated with a defibrillator, which delivers a strong electric shock to restore normal heart rhythm. The defibrillator uses a capacitor charged to several thousand volts, with calculations revealing it stores 0.08 C of charge and releases 160 J of energy upon discharge. The average current delivered is calculated to be 40 A, resulting in an initial power output of 160,000 W. However, this power is only accurate at the start of discharge, as voltage decreases to zero by the end. Further discussion is needed to find alternative equations for calculating average power during the discharge process.
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Homework Statement


A heart dysfunction that can cause death is ventricular fibrillation. This is an
uncoordinated quivering of the heart as opposed to regular beating. An electric shock to
the chest can cause momentary paralysis of the heart muscle, after which the heart will
sometimes start organized beating again. A defibrillator is a device that applies a strong
electric shock to the chest over a time of a few milliseconds. The device contains a
capacitor of several microfarads, charged to several thousand volts. Electrodes called
paddles, about 8 cm across and coated with conducting paste, are held against the chest
on both sides of the heart. Their handles are insulated to prevent injury to the operator,
who calls “Clear!” and pushes a button on one paddle to discharge the capacitor through
the patient's chest.


Assume that the capacitor in the defibrillator is 20.0 μF and is charged to 4,000 Volts.

a. How much charge is stored in the capacitor before it is discharged?
b. How much energy is released when the capacitor is discharged?
c. If the capacitor completely discharges in 2.0 ms, what is the average current
delivered by the defibrillator?
d. What is the average power delivered?


Homework Equations


C= Q/V
Energy stored= 1/2 C*V^2
I = Q\t
P=I*V


The Attempt at a Solution



a. How much charge is stored in the capacitor before it is discharged?
C= Q/V
Q = C*V = 20E-6 * 4000 = .08 C

b. How much energy is released when the capacitor is discharged?
Energy stored= 1/2 C*V^2 = 1/2 (20E-6)(4000^2 = 160 J

c. If the capacitor completely discharges in 2.0 ms, what is the average current
delivered by the defibrillator?
I = Q/t = .08/.002 = 40 A

d. What is the average power delivered?
P = I*V = 40 (4000)= 1.6X10^5W


I don't know if i did this problem right can someone help me
 
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a, b, and c look good.

A problem with d:
V is 4000v only at the beginning of the discharge, and drops to 0V by the end of the discharge. So P=I*V=1.6X10^5W is only true at the beginning; the average power will be less.

Do you know any other equations that deal with power?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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