Defining a Vector Space over Q: Can It Be Done?

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Defining a vector space over the field of rational numbers (Q) is valid, as Q is indeed a field. The example given, V=Q^2 over Q, adheres to the properties of a vector space, ensuring that operations remain within the field of rational numbers. The discussion highlights the importance of understanding vector space axioms, particularly for those new to proofs. Overall, the concept of a vector space over Q is sound and aligns with established mathematical principles. Clarification and support for understanding these concepts are encouraged.
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Homework Statement


I'm trying to define a vector space over Q. Does this make any sense?


Homework Equations


The properties of a vector space


The Attempt at a Solution



Let V=Q^2 over Q. It seems to me that everything would be defined and I shouldn't be able to do anything to a vector in this space to make it become an irrational or anything else that could let it step outside the field, so all the axioms of a vector space should hold.

This is the first class I've taken that actually deals with proofs, and I'm not following along too well. I was just wondering if you could do this. It seems quite similar to something like, Let V=R^2 over R.

So if I have something wrong here or make completely no sense, help would be appreciated. Thank you!
 
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Since scalars are taken from a field, and Q is certainly a field, your definition makes sense.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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