Definite Intergrals applied to area

[elitespart]

1. y=sec^{2}x and y=e^{2x}, in Quadrant I, for x\leq1. I need to calculate the area.



2. fundamental theorem



3. I'm using 0 and 1 as my lower and upper bounds and the answer I'm getting is -1.637 which is not reasonable. When I integrate using the calculator it's coming out to be 1.557. Where am I going wrong? Here's my work: (tan(1)-e^{2}/2) - (tan(o) - e^{0}/2)

Thanks.

 

[Dick]

Your answer is right, except that e^(2x)>sec^2(x) on that range, so you have an extra minus sign. I can't say what your calculator's problem is.

 

[elitespart]

Alright thanks for your help. Appreciate it.