1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Definite Intergrals applied to area

  1. Dec 18, 2007 #1
    1. y=sec[tex]^{2}x[/tex] and y=e[tex]^{2x}[/tex], in Quadrant I, for x[tex]\leq[/tex]1. I need to calculate the area.

    2. fundamental theorem

    3. I'm using 0 and 1 as my lower and upper bounds and the answer I'm getting is -1.637 which is not reasonable. When I integrate using the calculator it's coming out to be 1.557. Where am I going wrong? Here's my work: (tan(1)-e[tex]^{2}[/tex]/2) - (tan(o) - e[tex]^{0}[/tex]/2)

  2. jcsd
  3. Dec 18, 2007 #2


    User Avatar
    Science Advisor
    Homework Helper

    Your answer is right, except that e^(2x)>sec^2(x) on that range, so you have an extra minus sign. I can't say what your calculator's problem is.
  4. Dec 18, 2007 #3
    Alright thanks for your help. Appreciate it.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook