Definition of the gradient operator

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 3K views
elgen
Messages
63
Reaction score
5
Hi,

I am curious if anyone here remembers the gradient operator by the following definition:

[tex]\nabla f = \lim_{\Delta v->0} \frac{1}{\Delta v}\oint f \vec{dS}[/tex].

So far I could find only one book that gives the definition above.

I find this definition quite nice as the expressions of the gradient operator in many coordinate systems naturally follow from this definition. Also, it is a good contrast with the definition of the divergence operator

[tex]\nabla \cdot \vec{f} = \lim_{\Delta v->0} \frac{1}{\Delta v}\oint \vec{f}\cdot \vec{dS}[/tex].

notice the change from [tex]f[/tex] to [tex]\vec{f}[/tex].elgen
 
Last edited:
Physics news on Phys.org
I haven't seen those before. Did you mean to have [tex]\nabla f[/tex] and [tex]\Delta f[/tex] on the left hand sides, and [tex]\nabla f[/tex] in the integrand of the second?
 
Fixed my original post. They are the definition in terms of the limit.