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- Thread starter shooride
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haushofer

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The Vielbein's DOF's are easy (of-shell): it's a matrix, so it has D^2 components in D dimensions. Local Lorentz transformations make you subtract 1/2*D*(D-1) components from it, leaving you with 1/2*D*(D+1) components for the metric. Which is the right amount for a symmetric tensor like the metric.

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The Vielbein's DOF's are easy (of-shell): it's a matrix, so it has D^2 components in D dimensions. Local Lorentz transformations make you subtract 1/2*D*(D-1) components from it, leaving you with 1/2*D*(D+1) components for the metric. Which is the right amount for a symmetric tensor like the metric.

dear haushofer,I want to obtain the DOF of gravitino, but I just found the final answer at Supergravity by Freedman and Van Proeyen..I know gravitino has 2^[d/2](d-1) components in the off-shell formalism (i use local susy gauge invariance)..but I don't understand how to obtain DOF of gravitino in the on-shell formalism? (with E.O.M ##\gamma^\mu\psi_\mu=0## ) The answer is 2^[d/2]/2(d-3). Moreover I find at the book of SUGRA by West witch superveilbein (not vielbein) has 8*8*8 DOF (and general coordinate transformations and super local lorentz transformations subtract 8*8+8*6 components ) in 4-dim, but how to count these DOF?

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haushofer

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