Degrees and how it relates to slope

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SUMMARY

The relationship between slope and degree angles is defined by the tangent function, where the slope of a straight line corresponds to the tangent of the angle it forms with the x-axis. Specifically, a degree of 1 results in a slope of 1/57.29, a degree of 2 yields a slope of 1/28.9916, and a degree of 3 corresponds to a slope of 19.08109. This indicates that as the degree increases, the slope increases non-linearly, and the relationship can be expressed mathematically as slope = tan(θ) = 1/cot(θ).

PREREQUISITES
  • Understanding of trigonometric functions, specifically tangent and cotangent.
  • Basic knowledge of angles and their measurement in degrees.
  • Familiarity with the concept of slope in geometry.
  • Ability to interpret mathematical relationships and functions.
NEXT STEPS
  • Research the properties of the tangent function in trigonometry.
  • Explore the relationship between angles and slopes in calculus.
  • Learn about the cotangent function and its applications.
  • Investigate graphical representations of slope and angle relationships.
USEFUL FOR

Students studying mathematics, educators teaching geometry and trigonometry, and anyone interested in understanding the mathematical relationship between angles and slopes.

Ghost803
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Sorry if this question is too simple and shouldn't be posted here.

How does slope relate to degree angles?

For example , a degree of 1 means a slope of 1/57.29, and a degree of 2 means a slope of 1/28.9916, and a degree of 3 means a slope of 19.08109. and the slope just keeps getting larger and larger but its not being multiplied by two or anything. So does anyone know a function that can describe the relationship between two?
 
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Can a moderator please delete this thread. Sry for the inconvenience.
 
How about if I just move it to "general math" because it is an interesting question.

The "slope" of a straight line is the tangent of the angle the line makes with the x- axis
Since you are writing the slope as "1 over something" you need:

slope= tan(\theta)= 1/cot(\theta)
 

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