Perpendicular Lines: Slope, Angle & Equations

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SUMMARY

Two lines are perpendicular if the product of their slopes equals -1. Given the equations y = ax + b and g = cx + d, the condition for perpendicularity is expressed as ac = -1. The slope of a line is indeed the tangent of the angle between the line and the x-axis, confirming the relationship between slope and angle in trigonometric terms.

PREREQUISITES
  • Understanding of linear equations in the form y = mx + b
  • Basic knowledge of slopes and their geometric interpretation
  • Familiarity with trigonometric functions, particularly tangent
  • Concept of angles in relation to the Cartesian coordinate system
NEXT STEPS
  • Study the derivation of the condition for perpendicular lines in coordinate geometry
  • Explore the relationship between slopes and angles in trigonometry
  • Learn about the implications of perpendicularity in vector mathematics
  • Investigate applications of perpendicular lines in real-world scenarios, such as engineering and architecture
USEFUL FOR

Students of mathematics, geometry enthusiasts, educators teaching coordinate geometry, and anyone interested in the applications of trigonometry in understanding line relationships.

Taturana
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A very simple and noob question, sorry for this.

Looking at http://en.wikipedia.org/wiki/Perpendicular I found that two lines are perpendicular if and only if the product of their slopes is -1.

If I have two lines described by the following equations:

y = ax + b
g = cx + d

then they're perpendicular if ac = -1 right? Okay...

What's the explanation for this? How do I conclude that they're only perpendicular if and only if the product of their slopes is -1?

Just another little question: the slope of a line is the tangent of the angle between the line and the x-axis? that's right?

Thank you
 
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HI Taturana! :smile:
Taturana said:
How do I conclude that they're only perpendicular if and only if the product of their slopes is -1?

Just another little question: the slope of a line is the tangent of the angle between the line and the x-axis? that's right?

That's right :smile: … slope = tan, and so …

tan(90º + θ) = sin(90º + θ)/cos(90º + θ) = cosθ/(-sinθ) = -1/tanθ. :wink:

(or you can prove it just as easily by drawing it)
 

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