Delta Sign Confusion: Solving Depth of Grand Canyon

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SUMMARY

The discussion centers on calculating the depth of the Grand Canyon based on the time it takes for a yodel to echo back, which is 5.20 seconds. The speed of sound in air is given as 340.0 m/s. The correct approach to find the depth involves using the formula for distance, where distance equals speed multiplied by time. The depth of the canyon is calculated as half the total distance traveled by the sound wave, resulting in a depth of 884 meters.

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  • Familiarity with kinematic equations and their applications.
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ashley_bryant
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Homework Statement


Hans stands at the of the Grand Canyon and yodels down to the bottom. He hears his yodel echo back from the canyon floor 5.20s later. Assume that the speed of sound in air is 340.0m/s. How deep is the canyon at this location?

I made a chart.
Velocity Original = 340
Velocity Final= Unknown
Distance= x
Gravity = 9.81
Time = 5.20

The equation I'm using is
vf=vo+g(DELTA)t

I pretty much do the equation, I just need to know what I need to do for delta. (divide, mulitply, etc. I'm in Physics PRE-AP, Algebra, 9th grade. Advanced classes, blah.)


Homework Equations


Not sure what you mean?


The Attempt at a Solution


I plugged in the numbers:
vf= 340 + 9.81 (DELTA) 5.20

For delta, I used division. (VF-VO/G = T?)
I plugged in the numbers:
0-340/9.81
I got -34.65
This is probably wrong... >_<
 
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The equation you need is simply s=\frac{d}{t} . Sound is a pressure wave and doesn&amp;#039;t behave like a kinematic particle. Its speed is essentially constant.
 

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