If you were to throw a large log over the edge of the Grand Canyon and it took 5.65 seconds to hit the ground, calculate the velocity of the log at impact in m/s and calculate the distance the log fell in feet.
vf=vi + at, s=d/t
The Attempt at a Solution
So, I don't see any initial velocity in the question, which is weird because it says 'throw'..so that's a bit confusing. Do I just make it zero? Well, if I did, I'd get vf=55.4m/s. Now, for the distance part, I'm assuming I could just use the speed formula? (55.4)=d/(5.65) , and then I get 313.01 meters...(and an even larger number when converted into feet)...the problem is that the answer is 156.4 m.....how????