Delta-Y transformation of resistors

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Discussion Overview

The discussion revolves around the Delta-Y transformation of resistors, specifically focusing on deriving the conductance transformation equation from the resistor transformation equations. The context is primarily homework-related, with participants attempting to clarify their understanding of the algebra involved in the transformation process.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents an equation for the transformation from Delta to Y, specifically for conductance, and expresses confusion about the derivation leading to a different result than expected.
  • Another participant suggests that there may be an algebraic error and requests to see the detailed work to identify the issue.
  • A participant provides a detailed breakdown of their transformation steps but is questioned about a specific transition in their calculations.
  • There is acknowledgment of a misunderstanding regarding the algebra involved, with one participant realizing their mistake after further discussion.

Areas of Agreement / Disagreement

The discussion does not reach a consensus on the correct transformation equation, as participants are still working through the algebra and identifying errors. Multiple viewpoints on the correct approach and potential mistakes remain present.

Contextual Notes

Participants express uncertainty about specific algebraic steps and the need for clarity in the transformation process. There are indications of missing details in the calculations that prevent full verification of the claims made.

Who May Find This Useful

This discussion may be useful for students or individuals studying electrical engineering or circuit theory, particularly those interested in resistor transformations and conductance calculations.

franktherabbit
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Homework Statement


Starting from the expression of the Delta-Y resistor transformation work out the conductance transformation equation.

Homework Equations


3. The Attempt at a Solution [/B]
I will just be using one equation as others are done analogically. My Δ has ##(R_{12},R_{23},R_{13})## and my
γ has ##(R_1,R_2,R_3)##.
The first equation of transformation goes:
##R_1=\frac{R_{12}*R_{31}}{R_{12}+R_{23}+R_{13}}##
When i use that ##R=\frac{1}{G}## i get that
##G_1=\frac{G_{12}+G_{23}+G_{31}}{G_{23}}## which is not what they get. They get the same equation you get for Y-Delta transformation except for R u write G. ow did they get to that? I used a logical move and it can't get that way. What am i missing?
 
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franktherabbit said:
I used a logical move and it can't get that way. What am i missing?
Must be an algebra issue somewhere... but we can't tell you what's missing since it's almost all missing --- we can't check what we can't see :smile:

Can you show your work in detail?
 
Sure, :).
##R_1=\frac{R_{12}*R_{31}}{R_{12}+R_{23}+R_{31}}##
##G_1=\frac{1/G_{12}+1/G_{23}+1/G_{31}}{1/G_{12}*1/G_{31}}##
##G_1=\frac{(G_{12}+G_{23}+G_{31})/(G_{12}*G_{23}*G_{31})}{1/(G_{12}*G_{31})}##
##G_1=\frac{G_{12}+G_{23}+G_{31}}{G_{23}}##
See it? :)
 
I don't see how you went from your second line to your third. You haven't involved he denominator yet, so everything must be happening in the numerator. There you should end up with a sum of products divided by a product since all the terms are different.
 
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gneill said:
Must be an algebra issue somewhere... but we can't tell you what's missing since it's almost all missing --- we can't check what we can't see :smile:

Can you show your work in detail?

gneill said:
I don't see how you went from your second line to your third. You haven't involved he denominator yet, so everything must be happening in the numerator. There you should end up with a sum of products divided by a product since all the terms are different.
Ohhh, i see now, i had this all wrong. Turns out algebra is the killer here. Thanks man! :D
 
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