Density Error Propagation/Significant Figures Based on Extreme Values

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SUMMARY

The discussion focuses on calculating the density of an object with a mass of 976 g (±5 g) and a volume of 1 L (±0.01 L) using extreme values. The upper limit of density is calculated as (976 + 5) / (1 - 0.01), while the lower limit is (976 - 5) / (1 + 0.01). The challenge arises in determining the correct number of significant figures for the resulting density values, with the consensus that the density should reflect the precision of the least precise measurement, which is the volume with one significant figure.

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Homework Statement


The density of an object is found to be 976 g/L based on mass of 976 +/- 5g and volume of 1 +/- 0.01L.

Determine the error in the density using extreme values (upper limit of mass divided by lower limit of volume, etc)

Homework Equations


I'm having difficulty determining how to factor in significant figures here.

Use D = M / V

The Attempt at a Solution


Upper limit = (976 + 5) / (1 - 0.01)
Lower limit = (976 - 5) / (1 + 0.01)

My reasoning: since the numerator result has 3 significant figures, and the denominator has 1 significant figure (since 1 only has 1sigfig), the resultant densities have 1 sigfig. But this seems to cut off too many figures.
 
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Not all zeros are insignificant. Calculate both densities using all given digits and decide from those values the number of significant digits of the density.

ehild
 

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