Hi everyone, I have the following exercise. Fx(x)=0, x<-1 or x>1 Fx(x)=1/2, x=[-1;1] g(x)=x^2+1 --- this is the function of random variable I must calculate Fy which is the sum of solutions of g(xk)=y , Fy(y)=sumFx(xk)/|g`(xk)| g(x) is bijective on [-1;1] y=x^2+1=> x=+sqrt(y-1) or x=-sqrt(y-1), since x=[-1;1] both are posible solutions. And my question is on what interval is Fy defined... to find the intervals i use the formula [g(-1);g(1)] but i dont know if its right and in this case g(-1)=g(1)=2; What i am doing wrong??? On a similar exercise i had Fx(x)=1/2, x=[0;2] Fx=0, out of the interval g(x)=x^2+3 g`(x)=2x x=sqrt(y-3) and x=-sqrt(y-3), since x=[0;2], x=-sqrt(y-3) is not a posible solution. Fy(y)=sumFx(xk)/|g`(xk)|=1/4*1/sqrt(y-3)) So Fy(y)=1/4*1/sqrt(y-3) for y=[g(0)=3;g(2)=7]; Fy(y)=0 for y =[-infinite;3]U[7;+infinite] On seminars we did only with g(x)=a*x+b which was easy and these are for homework.