I Density parameter and curvature index

Ranku
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For Ω=1, κ=0. Does the value of κ simply follow from the value of Ω, or can its value have an independent existence? So if Ω>1, does κ have to be 1?
 
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Context would be useful. I don't want to guess what you mean.
 
Ranku said:
So if Ω>1, does κ have to be 1?
Yes, by definition. Since Ω=1 is the critical density - the density at which the universe is flat - any other value of Ω necessitates that the k parameter is not 0 and has the same sign as Ω-1.
 
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Likes Jaime Rudas and Ranku
Define k for me.
 
The definition of k seems to have more than one option. For example the (-1,0,1) option simplifies your question.
 
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