Ranku
- 434
- 18
For Ω=1, κ=0. Does the value of κ simply follow from the value of Ω, or can its value have an independent existence? So if Ω>1, does κ have to be 1?
The discussion centers on the relationship between the density parameter (Ω) and the curvature index (κ) in cosmology. It is established that for a critical density of Ω=1, κ equals 0, indicating a flat universe. If Ω exceeds 1, κ must be non-zero and share the same sign as Ω-1, confirming that κ cannot exist independently of Ω. The definition of κ can vary, with the (-1, 0, 1) classification providing a simplified understanding.
PREREQUISITESAstronomers, cosmologists, and physics students interested in the fundamental concepts of the universe's structure and dynamics.
Yes, by definition. Since Ω=1 is the critical density - the density at which the universe is flat - any other value of Ω necessitates that the k parameter is not 0 and has the same sign as Ω-1.Ranku said:So if Ω>1, does κ have to be 1?
See the discussion in the General Metric section of https://en.wikipedia.org/wiki/Friedmann–Lemaître–Robertson–Walker_metric, for example.mathman said:Define k for me.