1. The problem statement, all variables and given/known data A man drops a rock into a well. He hears the sound of the splash 3.2 seconds after he releases the rock from rest. The speed of sound in air (at the local ambient condition) is 338 m/s (a) How far below the top of the well is the surface of the water? (round your answer to a whole number) (b) If you ignored the travel time for the sound, what would have been the calculated depth? (round your answer to a whole number) time of rock + time of sound = 3.2s acceleration = -9.8 m/s^2 V_i = 0 m/s V_sound = 338 m/s 2. Relevant equations x=x_0 + v_0*t + (1/2)at^2 3. The attempt at a solution x = 0 + 0 + (1/2)(-9.8)(3.2)^2 However, I realized, this is incorrect because I also need to account the time the sound took to travel to the person's ear subtracted by the 3.2 seconds. My problem is, how do I find the time it took to reach the person's ear when the rock hit the surface of the water?