Derivation of momentum operator / origin of -ih d/dx

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SUMMARY

The discussion focuses on the derivation of the momentum operator in quantum mechanics, specifically the expression -iħ d/dx. The key steps involve recognizing that the momentum operator can be represented as p exp(ipx/ħ) = (ħ/i)(∂/∂x)exp(ipx/ħ). The interchange of integration and differentiation is crucial in this derivation, clarifying the relationship between momentum and wave functions. This understanding is essential for grasping the fundamentals of quantum mechanics.

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  • Quantum mechanics fundamentals
  • Understanding of wave functions
  • Familiarity with differential operators
  • Knowledge of the Planck constant (ħ)
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  • Study the derivation of the Schrödinger equation
  • Learn about the role of operators in quantum mechanics
  • Explore the concept of commutation relations
  • Investigate the implications of the momentum operator in quantum systems
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Students of quantum mechanics, physicists, and anyone interested in the mathematical foundations of the momentum operator in wave mechanics.

Juqon
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Homework Statement


In the derivation of the momentum operator: Why is this equal?


Homework Equations


[PLAIN]http://img268.imageshack.us/img268/4575/momentumoperatorderivat.png


The Attempt at a Solution


I thought maybe the integral is executed, but the integral sign stays.
One p vanishes, the momentum operator itself shows up.
You would really expect this in a derivation of p, but dp stays.
 
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There's two steps in there. First, you can write
p \exp\left(\frac{ipx}{\hbar}\right) = \frac{\hbar}{i}\frac{\partial}{\partial x}\exp\left(\frac{ipx}{\hbar}\right)
Then you interchange the order of integration and differentiation.
 
Now I see it. Thanks!
 

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