Derivation of r (radius) in terms of f (frequency)? Help please.

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Homework Help Overview

The discussion revolves around deriving an equation for the radius of an object in terms of its frequency, specifically in the context of a rotor machine, such as an amusement ride. Participants are exploring the relationships between linear velocity, angular velocity, frequency, and centripetal force.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to manipulate various equations to express radius in terms of frequency but expresses confusion over the number of variables involved. Some participants question the feasibility of deriving such a relationship without a clear context. Others suggest focusing on the role of centripetal force in the scenario presented.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on which equations might be relevant. There is an acknowledgment of the complexity of the task, and multiple interpretations of the problem are being explored without reaching a consensus.

Contextual Notes

Participants note that the original poster has been given limited information about the scenario, which may affect their ability to derive the desired equation. The discussion includes considerations of the physical forces at play in the rotor machine context.

BLZ
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Okay, so the job I need to do is derive an equation for the radius of an object in terms of its frequency.

These are the equations that we are allowed to use:

v(Linear velocity) = rω
v=2πr/T
ω (angular velocity)=2πf
f (frequency)= 1/T (time period)
T= 2πr/v
a (centripetal acceleration)=v^2/r
F (centripetal force)=mv^2/r

So now.. my attempt:

r= v/ω
= √ar/2πf
= (√(a*(vT/2π))/2πf
2πfr=√(a*(vT/2π)
2πfr^2= a * (vT/2π)
2π * 2πfr^2 = a * vT

... I'm lost I have so many variables that I need to eliminate and I'm not sure what else to do from here. Help would be very appreciated.
 
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Hi
I am not sure what you are trying to do. Radius and frequency are entirely different quantities and they are not directly related except when you state the situation that you are studying. You have written down some equations that relate them and some other quantities. What are you trying to achieve by jiggling around the original equations in the second half? I think you are trying for something that is impossible or has no meaning. Could you explain more fully, please?
 
sophiecentaur said:
Hi
I am not sure what you are trying to do. Radius and frequency are entirely different quantities and they are not directly related except when you state the situation that you are studying. You have written down some equations that relate them and some other quantities. What are you trying to achieve by jiggling around the original equations in the second half? I think you are trying for something that is impossible or has no meaning. Could you explain more fully, please?

okay, so the whole situation from what I've been told by my teacher is that we are deriving an equation for the radius in terms of frequency for a "rotor machine" aka the type of amusement rides that spin so fast that people are pushed against the walls and can't move. That is all the info that we've really been given for the equation. My teacher says this is a simple derivation but it seems very complicated to me. :(
 
Well, which of the equations you listed in the OP would be useful in figuring out how a person can be pushed up against the outer wall of the ride as it turns? What is keeping the person pressed up against the wall?
 
BLZ said:
okay, so the whole situation from what I've been told by my teacher is that we are deriving an equation for the radius in terms of frequency for a "rotor machine" aka the type of amusement rides that spin so fast that people are pushed against the walls and can't move. That is all the info that we've really been given for the equation. My teacher says this is a simple derivation but it seems very complicated to me. :(

So, now we know the actual scenario, the solution is fairly straightforward. You need a centripetal force to push your body inwards so that it doesn't slip. What sort of value could that involve? (Imagine how hard you would need to push a body against a rough wall, to stop it sliding down.) All you need now is to look in your equation tool box and find an equation that contains centripetal Force, speed and radius. Then arrange it so that F is one side and r is the other.

What did you expect, for such a sophisticated problem? But 'complication' is a very relative thing. :wink:
 
2nd attempt
Okay so I did rearranged an equation first to get...
√ar = v

and inserted it into the equation: F=mv^2/r
and got... F=m*(√ar^2)/r
= m*a*r/r
= ma

3rd attempt:
v = 2πr/T
√ar = 2πr/(2πr/v)
√ar = v ? (Cancelled itself out)

The wrong variables keep cancelling out for some reason. I've done quite the number of attempts and "r" keeps getting canceled out and that's one of the variables that I need. I'm not sure what I'm doing wrong? This equation has force, speed, and radius so did I pick the right equation to use or...?
 
Last edited:
Why are you surprised when the variables to cancel out? You can get all sorts of results when you substitute and reduce.
You start off with the right equation ( F=mv^2/r) and then shoot yourself in the foot by 'tidying it up' too much. Put in the value you think is appropriate for the Force and then you can rearrange to get how V and r are related. Job done, bish bash bosh!
 

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