- #1

mjordan2nd

- 177

- 1

My book defines the atomic form factor as

[tex]\int dV n_{j}(\vec{r})e^{-i \vec{G} \bullet \vec{r}}[/tex].

where n(r) is the electron density of the jth atom at r, and G is the reciprocal lattice vector. It says the above expression is equal to

[tex]2 \pi \int dr r^{2} d(cos \alpha) n_{j}(r) e^{-iGr cos \alpha}[/tex]

in the case that the electron distribution is spherically symmetric where alpha is the angle between the reciprocal lattice vector and r. I don't understand how the author goes from the first equation to the second. In fact, I'm not sure I'm comfortable with this d(cos) notation at all. If someone could point me to a site where I could read up about that, I would appreciate it. The author then proceeds to integrate d(cos) from -1 to 1. Why he does this is unclear to me as well. Any help is appreciated.

[tex]\int dV n_{j}(\vec{r})e^{-i \vec{G} \bullet \vec{r}}[/tex].

where n(r) is the electron density of the jth atom at r, and G is the reciprocal lattice vector. It says the above expression is equal to

[tex]2 \pi \int dr r^{2} d(cos \alpha) n_{j}(r) e^{-iGr cos \alpha}[/tex]

in the case that the electron distribution is spherically symmetric where alpha is the angle between the reciprocal lattice vector and r. I don't understand how the author goes from the first equation to the second. In fact, I'm not sure I'm comfortable with this d(cos) notation at all. If someone could point me to a site where I could read up about that, I would appreciate it. The author then proceeds to integrate d(cos) from -1 to 1. Why he does this is unclear to me as well. Any help is appreciated.

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