Derivation of the moment of inertia eqn for a thin spherical shell

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SUMMARY

The moment of inertia equation for a thin spherical shell can be derived from the equation for a hollow sphere: I = (2/5) M (Ro^5 - Ri^5)/(Ro^3 - Ri^3). To find the limit as Ri approaches Ro, one can rewrite the equation using Ro = Ri(1+δ), where δ is a small value. This approach allows for the application of the binomial theorem to simplify the terms and evaluate the limit. Integration can also be used to derive the moment of inertia for a spherical surface effectively.

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  • Understanding of moment of inertia concepts
  • Familiarity with limits and L'Hopital's Rule
  • Knowledge of the binomial theorem
  • Basic integration techniques
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  • Learn about the derivation of moment of inertia for different shapes
  • Explore integration techniques for calculating moment of inertia
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cubejunkies
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So I've been trying to derive the moment of inertia equation for a thin spherical shell and I've slammed into a dead end algebraically. I was able to derive an equation for a hollow sphere:

I = (2/5) M (Ro^5 - Ri^5)/(Ro^3 - Ri^3)

where Ro is the distance to the very outside of the sphere and Ri is the distance to the inner thickness of the sphere if that makes sense.

I thought I could take the limit as Ri approached Ro, to yield the rotational inertia of a very thin spherical shell as I sought out for, however, I cannot evaluate the limits even if I used L'Hopital's Rule and derived the top and bottom separately because that would not allow me to escape the cursed indeterminant form of 0/0 which results every time until the denominator goes away to zero and then I'm really in a bad situation.

I saw a website http://scienceworld.wolfram.com/physics/MomentofInertiaSphericalShell.html which reduced the (Ro^5 - Ri^5)/(Ro^3 - Ri^3) term using a series decomposition of some sort, but I have no idea what they did and it's been a while since I've meddled with Taloy Series and stuff, so any help with this or an explanation of what they did would be greatly appreciated.

THANKS! :)
Anthony
 
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For a very thin shell, Ro=Ri(1+δ), and δ is very small compared to 1. Rewrite your equation in terms of Ri and δ. Remember the binomial theorem, http://en.wikipedia.org/wiki/Binomial_theorem and expand Ro5 and Ro3. Find the limit of I when \stackrel{δ}{\rightarrow}0.

But it is easy to get I by integration for a spherical surface.

ehild
 
Wait, why does Ro=Ri(1+δ) ? I don't get the (1+δ) part. I also tried expanding as they did on that webpage listed above, using Ro = Ri + r and expanding that, but I can't cancel stuff down like they did and the magical appearance of the factorials in the last step confuses me.

Thanks
Anthony
 
OH WAIT NEVERMIND haha I did some algebraic gymnastics and figured it out :)
 
You are an excellent sportsman!:wink: Don't you try the integration?

ehild
 

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