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Derivation of y = bt^2 for velocity and acceleration

  1. Sep 11, 2012 #1
    1. The problem statement, all variables and given/known data

    The altitude of the space shuttle during the first 30 s of its ascent is described by the expression у = bt2, where the constant b has the value 2.9 m/s2. Using calculus, obtain an expression for the velocity and acceleration of the space shuttle during this period.


    3. The attempt at a solution

    y' = 2bt
    y'' = 2b

    Book is giving me the following for answers:
    y' = bt
    y'' = b

    Am I doing something wrong?
     
  2. jcsd
  3. Sep 11, 2012 #2

    PhanthomJay

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    No, your answers are OK, as long as you are sure which is velocity and which is acceleration. I have no idea what the book was thinking by giving those answers.
     
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