When Does the Angular Velocity of a DC Motor Reach Zero?

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The discussion centers on determining when the angular velocity of a DC motor reaches zero after reversing the current. The angular displacement is given by a cubic equation, and confusion arises regarding the correct application of calculus to find the time at which the angular velocity is zero. Participants emphasize the importance of correctly identifying coefficients and ensuring physical relevance of the solutions. To find the number of revolutions the motor shaft turns before reaching zero angular velocity, the time derived must be substituted back into the angular displacement equation, followed by converting radians to revolutions. The conversation highlights the need for careful attention to detail in both calculations and unit conversions.
nateshoe
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Homework Statement



At t=0 the current to a dc electric motor is reversed, resulting in an angular displacement of the motor shaft given by theta (t) = ( A)t-( B)t^{2}-( C)t^{3}

At what time is the angular velocity of the motor shaft zero?

Homework Equations



quadratic

The Attempt at a Solution



I continue to be very confused by this question. I thought all I need to do was take the derivative with respect to time and then plug those coefficients into the quadratic equation.
So I get:

(2B(+/-)((4B^2+12AC)^.5))/2A
 
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1. You have interchanged the roles of A and -3C here, so your expression is not correct.
2. Which of the times you get out is not physically meaningful?
 
Well I got that part figured out but I can't get the next part.

1.
How many revolutions does the motor shaft turn through between the time when the current is reversed and the instant when the angular velocity is zero?
2.
Deltatheta=.5(w+w0)t
revolution=(1/2pi)radians
3.
Since the final velocity is zero:
deltatheta=.5tw0
revolutions=(.5tw0)/(2pi)
w0=A
so;

=.5tA/2pi (where t is the time when angular velocity =0)


Thanks,
Nate
 
Question: How many revolutions does the motor shaft turn through between the time when the current is reversed and the instant when the angular velocity is zero?

Ans: Well, assuming that you found the time t when the angular velocity is zero, all you need to find out here is the revolutions between zero and that time t.

Plug in the time t into the angular displacement equation that you have, and you should get something in radian measure.

Then, the next thing that tricked me out was that I didn't know the conversion from radian to revolutions. (a simple thing, I know, but I overlooked it)

1 revolution = 2*pi radians.

Convert, and viola you have how many revolutions.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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