Derivative Homework: Checking Answers with Step-by-Step Solutions

Click For Summary

Homework Help Overview

The discussion revolves around checking homework solutions related to derivatives, specifically focusing on the correctness of expressions and the application of derivative concepts in the context of a given problem set.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are examining the correctness of derivative calculations and expressions, questioning the equality of different forms of the derivative, and discussing the implications of notation such as C' versus specific values like C'(81).

Discussion Status

Some participants have provided feedback on specific mistakes identified in the original poster's work, while others have clarified the distinction between general and specific derivative evaluations. There is an ongoing exploration of the implications of these distinctions without a clear consensus on all points raised.

Contextual Notes

Participants are addressing potential misunderstandings in derivative notation and calculations, indicating that the original poster may have overlooked certain details in their expressions. The discussion is framed within the constraints of homework checking, emphasizing the need for clarity in mathematical reasoning.

Nope
Messages
100
Reaction score
0

Homework Statement


Can someone check my homework?
http://img10.imageshack.us/img10/9686/48742895.jpg
http://img229.imageshack.us/img229/6981/52780988.jpg
http://img297.imageshack.us/img297/6955/85086758.jpg
http://img11.imageshack.us/img11/1221/86324492.jpg
thx!

Homework Equations





The Attempt at a Solution

 
Last edited by a moderator:
Physics news on Phys.org


In problem 2 you have a mistake.
You have
C = 2sqrt(A*pi) = 2(A*pi)^(1/2) = (A*pi)^(-1/2) *pi

The 2nd and 3rd expressions above are not equal. You have apparently taken the derivative, but you show it as being equal to C. The derivative of C is not equal to C.
 


Mark44 said:
In problem 2 you have a mistake.
You have
C = 2sqrt(A*pi) = 2(A*pi)^(1/2) = (A*pi)^(-1/2) *pi

The 2nd and 3rd expressions above are not equal. You have apparently taken the derivative, but you show it as being equal to C. The derivative of C is not equal to C.

Oh, I forgot to put C'!
Is that the only mistake i got?
 


You got the right answer, but make sure you understand the difference between C'(A) and C'(81)

C'(A) = sqrt(pi/A)
C'(81) = sqrt(pi/81) [itex]\approx[/itex] .1969

Another way to write what you're doing is this:

[tex]\frac{\Delta C}{\Delta A} \approx \frac{dC}{dA}[/tex]
[tex]\Rightarrow \Delta C \approx \frac{dC}{dA} \Delta A[/tex]
[tex]\Rightarrow \Delta C \approx \frac{dC}{dA}|_{A = 81} \Delta A[/tex]
[tex]\approx .1969 * 1 = .1969[/tex]

Everything looks fine for the other problem.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
5
Views
2K
Replies
6
Views
11K
Replies
5
Views
2K
Replies
8
Views
3K