Derivative *of* a partial derivative

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The discussion centers on understanding the concept of taking the derivative of a partial derivative, particularly in the context of the Lagrangian function. A participant explains that this process involves differentiating with respect to time after already having taken a partial derivative, which they find straightforward. The original poster expresses a desire for deeper understanding and finds clarity through a video by Leonard Susskind that discusses related concepts in classical mechanics. The exchange highlights the importance of grasping both the mechanics and the underlying principles of calculus in physics. Overall, the conversation emphasizes the connection between theoretical understanding and practical application in advanced calculus.
Pollywoggy
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Homework Statement



In books I have been using to learn about the Lagrangian function, I find equations that have a derivative of a partial derivative, as in the snippet below. Is there a place where I can learn how this works and *why* it works? I think I can do it mechanically but I want to understand what I am doing. What type of calculus books would have an explanation of it, advanced calculus books?



Homework Equations



\frac{d}{dt} (\displaystyle \frac{\partial T}{\partial \dot{q}_\alpha})
 
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What do you mean HOW does it work... You're just taking the derivative of something that has already been derivated.

It's like

F(x,t) = xe^{t^{2}}

\frac{\partial F}{\partial x} = e^{t^{2}}

\frac{d}{dt}(\frac{\partial F}{\partial x}) = 2te^{t^{2}}

To me it's fairly straightforward.. You're just taking a derivative wrt time of a derivative wrt something else. I don't understand what you mean when you ask 'WHY' this works.
 
Clever-Name said:
What do you mean HOW does it work... You're just taking the derivative of something that has already been derivated.

It's like

F(x,t) = xe^{t^{2}}

\frac{\partial F}{\partial x} = e^{t^{2}}

\frac{d}{dt}(\frac{\partial F}{\partial x}) = 2te^{t^{2}}

To me it's fairly straightforward.. You're just taking a derivative wrt time of a derivative wrt something else. I don't understand what you mean when you ask 'WHY' this works.

Thanks, I think you just answered my question :)
As I was reading your reply, I was watching one of Leonard Susskind's videos and he happened to be explaining something involving the Lagrangian function and I think he also answered my question. I am going to go over that part of the video again. It's #4 in the Phys 25 (Classical Mechanics) series, where he discusses symmetry and the "action".
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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