Derivative *of* a partial derivative

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SUMMARY

The discussion centers on understanding the derivative of a partial derivative, particularly in the context of the Lagrangian function. A user inquires about resources to grasp the concept beyond mechanical application. The response clarifies that taking the derivative with respect to time of a previously derived function is straightforward, illustrated with the example of the function F(x,t) = xe^{t^{2}}. The user finds clarity through Leonard Susskind's video on the Lagrangian function, specifically in his Phys 25 (Classical Mechanics) series.

PREREQUISITES
  • Understanding of partial derivatives
  • Familiarity with the Lagrangian function
  • Basic knowledge of calculus, particularly differentiation
  • Exposure to classical mechanics concepts
NEXT STEPS
  • Watch Leonard Susskind's Phys 25 (Classical Mechanics) series, especially video #4 on symmetry and action
  • Study advanced calculus textbooks that cover derivatives of derivatives
  • Explore resources on the Lagrangian mechanics framework
  • Review examples of applying derivatives in physics problems
USEFUL FOR

Students of physics, particularly those studying classical mechanics, as well as anyone seeking to deepen their understanding of calculus and its applications in theoretical frameworks like the Lagrangian function.

Pollywoggy
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Homework Statement



In books I have been using to learn about the Lagrangian function, I find equations that have a derivative of a partial derivative, as in the snippet below. Is there a place where I can learn how this works and *why* it works? I think I can do it mechanically but I want to understand what I am doing. What type of calculus books would have an explanation of it, advanced calculus books?



Homework Equations



\frac{d}{dt} (\displaystyle \frac{\partial T}{\partial \dot{q}_\alpha})
 
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What do you mean HOW does it work... You're just taking the derivative of something that has already been derivated.

It's like

F(x,t) = xe^{t^{2}}

\frac{\partial F}{\partial x} = e^{t^{2}}

\frac{d}{dt}(\frac{\partial F}{\partial x}) = 2te^{t^{2}}

To me it's fairly straightforward.. You're just taking a derivative wrt time of a derivative wrt something else. I don't understand what you mean when you ask 'WHY' this works.
 
Clever-Name said:
What do you mean HOW does it work... You're just taking the derivative of something that has already been derivated.

It's like

F(x,t) = xe^{t^{2}}

\frac{\partial F}{\partial x} = e^{t^{2}}

\frac{d}{dt}(\frac{\partial F}{\partial x}) = 2te^{t^{2}}

To me it's fairly straightforward.. You're just taking a derivative wrt time of a derivative wrt something else. I don't understand what you mean when you ask 'WHY' this works.

Thanks, I think you just answered my question :)
As I was reading your reply, I was watching one of Leonard Susskind's videos and he happened to be explaining something involving the Lagrangian function and I think he also answered my question. I am going to go over that part of the video again. It's #4 in the Phys 25 (Classical Mechanics) series, where he discusses symmetry and the "action".
 

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