Derivative of an absolute value

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SUMMARY

The derivative of the absolute value function is defined as \(\frac{d}{dx}[|u|]=\frac{u}{|u|}(u')\). This formula applies universally to any differentiable function \(u\), provided that \(u\) is not equal to zero. For example, when using \(u = x\), the derivative \(\frac{d}{dx}(|x|)\) simplifies to \(\frac{x}{|x|}\), yielding 1 for \(x > 0\) and -1 for \(x < 0\). The critical point is that the absolute value function is not differentiable at \(u = 0\).

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  • Understanding of basic calculus concepts, particularly derivatives.
  • Familiarity with piecewise functions and their properties.
  • Knowledge of differentiability and points of non-differentiability.
  • Proficiency in applying the chain rule in differentiation.
NEXT STEPS
  • Study the properties of piecewise functions in calculus.
  • Explore the concept of differentiability and its implications in real analysis.
  • Learn about the chain rule and its application in more complex functions.
  • Investigate the behavior of functions at points of non-differentiability.
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Students of calculus, mathematics educators, and anyone seeking to deepen their understanding of derivatives, particularly in relation to absolute value functions.

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I don't get why: \frac{d}{dx}[|u|]=\frac{u}{|u|}(u&#039;)

Can someone give me an example to which this applies? Can you use any function in place of "u"?
 
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but you'd need to know that that isn't differentiable at u=0

and for u>0 ,|u|=u
and for u<0,|u|=-u

for example take |x|

\frac{d}{dx}(|x|)=\frac{x}{|x|}


for x>0 ,|x|=x

and so \frac{d}{dx}(x)=\frac{x}{x}=1 which is true. Take x<0 and it'll also hold true.
 
You can use any differentiable function in place of u.

Do what you always do with an absolute value: consider cases u(x)>0 and u(x)< 0 separately.
 

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