Derivative of det(g): Confirmation Needed

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The derivative of the determinant of the metric tensor, denoted as g=\det(g_{\mu\nu}), is confirmed to be \frac{\partial g}{\partial g^{\mu\nu}}=-gg_{\mu\nu}. This conclusion is established and supported by the participants in the discussion, affirming the correctness of the derivative calculation in the context of differential geometry.

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pellman
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Given [itex]g=\det(g_{\mu\nu})[/itex], I find that

[tex]\frac{\partial g}{\partial g^{\mu\nu}}=-gg_{\mu\nu}[/tex]

Can someone confirm if this is correct, please?
 
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Yes, that's correct.
 
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