Derivative of e^(1+lnx): Solving for y

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SUMMARY

The discussion focuses on solving the derivative of the function y = e^(1 + ln(x)). The user correctly applies logarithmic differentiation, leading to the expression y' = e^(1 + ln(x)) * (1/x). The simplification of e^(1 + ln(x)) to e * x is confirmed, allowing for further analysis of the derivative. The final expression for the derivative is y' = e * (1/x), which is essential for understanding the behavior of the function.

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Juwad
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hello,

i need some assistance on this problem:

y = e^(1+lnx)

1st. I brought down the (1+lnx) by using natural log on both sides.

lny*y'=(1+lnx)*lne
y'/y=(1/x)*1

y'=e^(1+lnx)*(1/x)

what do i do next?
 
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[tex]e^{1+\ln x}=e^1e^{\ln x}=ex[/tex]
 
thanks,!:-p
 

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