Derivative of e^(1+lnx): Solving for y

[Juwad]

hello,

i need some assistance on this problem:

y = e^(1+lnx)

1st. I brought down the (1+lnx) by using natural log on both sides.

lny*y'=(1+lnx)*lne
y'/y=(1/x)*1

y'=e^(1+lnx)*(1/x)

what do i do next?

 

[quasar987]

$$e^{1+\ln x}=e^1e^{\ln x}=ex$$

 

[Juwad]

thanks,!