Derivative of exponential functions

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Riles246
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Homework Statement



d/dT (e-E0/(kT))

Homework Equations



d/dx(ex) = ex

The Attempt at a Solution



e-E0/(kT) * E0/kT2 ?

Do you use the chain rule on the exponent of e?
 
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Riles246 said:

Homework Statement



d/dT (e-E0/(kT))

Homework Equations



d/dx(ex) = ex

The Attempt at a Solution



e-E0/(kT) * E0/kT2 ?

Do you use the chain rule on the exponent of e?
Looks spot on to me :approve:. And yes, you would use the chain rule (followed by the power rule on the exponent) to differentiate the function.
 
if u=u(x),
d/dx (e^u) = e^u du/dx
d/dx (e^(1/x)) = e^(1/x) (-1)/(x^2)
d/dx (e^(a/x)) = e^(a/x) (-a)/(x^2)
d/dx (e^(a/bx)) = e^(a/bx) (-a/b)/(x^2)