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Jrlinton

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1. Homework Statement

Find derivative of

y=e^(cos(t)+lnt)

So just using the chain rule:

y'=e^(cos(t)+lnt)*(-sin(t)+1/t)

The answer in the back of the book is

y'=e^(cos(t))*(1-tsin(t))

Find derivative of

y=e^(cos(t)+lnt)

## Homework Equations

## The Attempt at a Solution

So just using the chain rule:

y'=e^(cos(t)+lnt)*(-sin(t)+1/t)

The answer in the back of the book is

y'=e^(cos(t))*(1-tsin(t))

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