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Jrlinton
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1. Homework Statement
Find derivative of
y=e^(cos(t)+lnt)
So just using the chain rule:
y'=e^(cos(t)+lnt)*(-sin(t)+1/t)
The answer in the back of the book is
y'=e^(cos(t))*(1-tsin(t))
Find derivative of
y=e^(cos(t)+lnt)
Homework Equations
The Attempt at a Solution
So just using the chain rule:
y'=e^(cos(t)+lnt)*(-sin(t)+1/t)
The answer in the back of the book is
y'=e^(cos(t))*(1-tsin(t))
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