Derivative of f(t) = te^(2-7t)

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SUMMARY

The derivative of the function f(t) = te^(2-7t) is calculated using the product rule and the chain rule. The correct application of these rules yields f'(t) = t * d/dt(e^(2-7t)) + e^(2-7t) * d/dt(t), resulting in the final answer of f'(t) = e^(2-7t)(t * -7 + 1). The key steps involve differentiating the exponential function and applying the product rule correctly.

PREREQUISITES
  • Understanding of the product rule in calculus
  • Knowledge of the chain rule in calculus
  • Familiarity with exponential functions
  • Basic differentiation techniques
NEXT STEPS
  • Review the product rule and its applications in calculus
  • Study the chain rule and practice differentiating composite functions
  • Explore exponential function properties and their derivatives
  • Practice solving similar derivative problems involving products of functions
USEFUL FOR

Students studying calculus, particularly those learning about differentiation techniques, as well as educators looking for examples of applying product and chain rules in derivative calculations.

kxpatel29
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Homework Statement


What is the derivative of f(t) = te^(2-7t)


Homework Equations


We would use product rule and chain rule, I believe



The Attempt at a Solution


(t)(e^(2-7t)
(1)(e^(2-7t)(-7)

answer: -7(e^(2-7t))
 
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You are correct in saying that the product and chain rules are needed, however you neglected to apply the product rule.

f(t)=t*e2-7t
f'(t)=t*d/dt(e2-7t)+d/dt(t)*e2-7t
 

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