How Do You Correctly Apply the Product and Quotient Rules in Differentiation?

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SUMMARY

The discussion focuses on the correct application of the Product and Quotient Rules in differentiation, specifically for the equations y = 8sin(125t)e^-7t and s = (8x^2-7x +125)/(8x+7). The correct differentiation for the first equation utilizes the Product Rule as d(uv)/dt = v(du/dt) + u(dv/dt), while the second equation applies the Quotient Rule as (v(du/dx) - u(dv/dx))/v^2. The user initially misapplied the rules, leading to incorrect differentiation results.

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DBeckett91
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I have 2 separate equations that I have to finish, but my lecturer is extremely slow at marking and I need to get it marked off asap, so if you could give me a hand it would be hugely appreciated.

For all of these equations I need to differentiate with respect to the variable and give the final simplified answers.

Equation 1: y = 8sin(125t)e^-7t
The value of t is unknown

The rule I was using is u(dv/dx) + v(du/dx)

y=8sin(125t)e^-7t

u = 8sin(125t)
v = e^-7t

Answer = 8sin(125t) (7e^-7t/dx) + 7e^-7t(8sin(125t)/dx)

Equation 2: s = (8x^2-7x +125)/8x+7

The rule I used was (v(du/dx) - u(dv/dx)/v^2)

s = (8x^2-7x +125)/8x+7

u = 8x^2-7x +125
= 16x - 7

v = 8x + 7
= 8

ds/dx = (8(16x-7/dx) - 16x-7(8/dx))/64
 
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I assume that you're differentiating right? Then you're writing is wrong, you should write:

<br /> \frac{du}{dt}=8\times 125\cos (125t),\quad\frac{dv}{dt}=-7e^{-7t}<br />

So the product rule you should be using is d(uv)/dt=vdu/dt+udv/dt, there are no x's around. That is where you made your error.
 

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