Derivative of Pressure/Temperature: Explained

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racnna
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can someone please explain this?

[tex]\frac{d}{dt} \frac{P}{T}=\frac{1}{T} ( \frac{dP}{dt}- \frac{dlnT}{dt})[/tex]
 
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im not sure...

but i just tried quotient rule and it worked out?...
[tex]\frac{d}{dt} \frac{P}{T}= \frac{T \frac{dP}{dt}-P \frac{dT}{dt}}{T^2}=\frac{1}{T} \frac{dP}{dt} - \frac{P}{T^2} \frac{dT}{dt}[/tex] ...etc.
how exactly do you implement chain rule after you use product rule? i would like to know. thanks in advance!
 
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thanks!...i need to get used to using the chain rule...we never really used it much in my calculus classes from back in the day...