B Derivative of Square Root of x at 0

Click For Summary
The derivative of the square root function at x=0 is not defined using either the power rule or the limit definition of the derivative. The power rule yields 1/2(sqrt.x), which is undefined at 0. Similarly, applying the limit definition results in infinity, indicating a lack of a finite derivative at that point. Both methods highlight that the derivative does not exist at x=0 for the function x to the square root. Thus, the derivative of the square root function is undefined at this critical point.
mopit_011
Messages
17
Reaction score
8
When you use the power rule to differentiate the square root, the result is 1/2(sqrt. x) which is undefined at 0. But, when you use the definition of the definition of the derivative to calculate it, the result is infinity. What causes this difference between these two methods?
 
Physics news on Phys.org
Infinity is undefined in this context.
 
mopit_011 said:
When you use the power rule to differentiate the square root, the result is 1/2(sqrt. x) which is undefined at 0. But, when you use the definition of the definition of the derivative to calculate it, the result is infinity. What causes this difference between these two methods?
None. The derivative of ##x\longmapsto \sqrt{x}## isn't defined for ##x=0## in neither case.
 
Some might also observe that
$$\lim_{x\to 0^+} \frac{1}{2\sqrt{x}}$$
Is also infinity.
 

Similar threads

Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
26
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K