Derivatives of a higher order - Satisfying the equation

Click For Summary

Homework Help Overview

The problem involves verifying whether the function y = xex satisfies a second-order linear differential equation of the form A(d²y)/dx² + B(dy/dx) + Cy = 0, with appropriate constants A, B, and C. The subject area pertains to differential equations and their properties.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the necessary derivatives and substitute them into the differential equation but encounters difficulty in determining the constants A, B, and C due to the presence of x² terms. Some participants question the accuracy of the derivatives calculated.

Discussion Status

The discussion is ongoing, with some participants providing feedback on the calculations. There appears to be a recognition of a mistake in the derivative calculation, and the original poster is seeking clarification on where the error occurred.

Contextual Notes

There is an attachment referenced that presumably contains the original poster's work, which may include additional details or calculations relevant to the problem.

K.QMUL
Messages
54
Reaction score
0

Homework Statement



Show that y= xex satisfi es

A(d2y)/dx2 + B(dy/dx) + Cy = 0

for suitably chosen values of the constants A, B, and C.

Homework Equations



Y=xex

The Attempt at a Solution



Please see the attachment. I get to a point where I need to find the value of A, B and C but cannot as I'm dealing with x2 terms.

Help would be much appreciated.
 

Attachments

  • 20131015_172043.jpg
    20131015_172043.jpg
    31.5 KB · Views: 494
Physics news on Phys.org
You calculated dv/dx wrong.
 
Could you explain Where I went wrong?
 
Oh, I see the mistake, Thanks
 

Similar threads

Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
6
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
2K