- #1
fr33pl4gu3
- 82
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f(x) = ln (12x-5/9x-2)
f'(x) = (4/3) (1/ln10)(9x-2/12x-5)
Is this correct??
f'(x) = (4/3) (1/ln10)(9x-2/12x-5)
Is this correct??
This should not have ln inside. What is d/dx ln(12x-5) ? You've got it from above, just put it into this one.fr33pl4gu3 said:(12/12(ln9x-2)-5)-(9/9x-2)
Derivatives of natural logarithmic functions refer to the rate of change of a natural logarithmic function at a specific point on its curve. In other words, it measures how much the function is changing at a particular point.
To find the derivative of a natural logarithmic function, you can use the following formula: d/dx (ln(x)) = 1/x. This means that the derivative of ln(x) is equal to 1 divided by x.
Derivatives of natural logarithmic functions are important because they help us understand the behavior of a function and its graph. They also have many applications in fields such as physics, economics, and engineering.
The chain rule for derivatives of natural logarithmic functions states that the derivative of ln(u) is equal to 1/u multiplied by the derivative of u. In other words, you can find the derivative of a natural logarithmic function with an inner function by first finding the derivative of the inner function and then multiplying it by 1/u.
One example of a natural logarithmic function is y = ln(x). Its derivative would be dy/dx = 1/x. This means that at any point on the curve of ln(x), the rate of change is equal to 1 divided by the x-value of that point.