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Derive 1-dimensional motion from average acceleration (no calculus)

  1. Sep 18, 2012 #1
    Starting with the expressions for average acceleration (Change in Velocity over Change in time), average velocity at constant acceleration; algebraically (NO CALCULUS) derive the equation for one-dimensional motion that relates displacement to the acceleration, assuming acceleration is constant.
     
  2. jcsd
  3. Sep 19, 2012 #2
    Sketch a graph of velocity vs. time and calculate the area under the graph.

    s=vt

    You can start v0 at any point and vf too.
     
  4. Sep 19, 2012 #3

    rcgldr

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    Homework Helper

    It can be derived based on the fact that with constant acceleration, for any time period, the average velocity during that time period is 1/2 the sum of the initial and final velocity.

    v0 = initial velocity
    v1 = final velocity
    v1 = v0 + at

    average velocity = 1/2 (v0 + v1) = 1/2 (v0 + (v0 + at) = v0 + 1/2 a t

    distance = initial position + average velocity x time

    x = x0 + (v0 + 1/2 a t) t = x0 + v0 t + 1/2 a t2
     
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