Derive cyclotron and synchrotron frequency

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SUMMARY

The discussion focuses on deriving the cyclotron and synchrotron frequency, highlighting the confusion surrounding the use of the term (v/c)qB in the derivation. The participant clarifies that 'c' refers to the speed of light, which leads to discrepancies when comparing this expression to the familiar SI unit formula (mv^2)/r. The distinction between CGS and SI units is emphasized as a critical factor in understanding these derivations.

PREREQUISITES
  • Understanding of Lorentz force in both CGS and SI units
  • Familiarity with the concepts of cyclotron and synchrotron motion
  • Basic knowledge of electromagnetic theory
  • Proficiency in algebra and unit conversion
NEXT STEPS
  • Study the derivation of cyclotron frequency in both CGS and SI units
  • Learn about the implications of using (v/c)qB in electromagnetic equations
  • Explore the differences between CGS and SI unit systems in physics
  • Investigate applications of cyclotron and synchrotron frequencies in particle physics
USEFUL FOR

Physicists, engineering students, and anyone involved in electromagnetic theory or particle motion analysis will benefit from this discussion.

Aziza
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I am trying to find out how to derive the cyclotron and synchrotron frequency, but everywhere I look it is derived by saying that the force of the magnetic field is not qvB, but (v/c)qB. What on Earth is this c? I am guessing it means speed of light but then it is not the case that (v/c)qB = (mv^2)/r...but that is what is says everywhere for this derivation. I have attached a snapshot of a website deriving it this way as an example.
 

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It's a matter of units.
The formula with c in it is the expression of Lorentz force in CGS units.
The one that you are more familiar with is in SI units.
 

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